(10/a^2)-(1/a)-2=0

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Solution for (10/a^2)-(1/a)-2=0 equation:


D( a )

a^2 = 0

a = 0

a^2 = 0

a^2 = 0

1*a^2 = 0 // : 1

a^2 = 0

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

10/(a^2)-(1/a)-2 = 0

10/(a^2)-a^-1-2 = 0

10*a^-2-a^-1-2 = 0

t_1 = a^-1

10*t_1^2-1*t_1^1-2 = 0

10*t_1^2-t_1-2 = 0

DELTA = (-1)^2-(-2*4*10)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+1)/(2*10) or t_1 = (1-81^(1/2))/(2*10)

t_1 = 1/2 or t_1 = -2/5

t_1 = -2/5

a^-1+2/5 = 0

1*a^-1 = -2/5 // : 1

a^-1 = -2/5

-1 < 0

1/(a^1) = -2/5 // * a^1

1 = -2/5*a^1 // : -2/5

-5/2 = a^1

a = -5/2

t_1 = 1/2

a^-1-1/2 = 0

1*a^-1 = 1/2 // : 1

a^-1 = 1/2

-1 < 0

1/(a^1) = 1/2 // * a^1

1 = 1/2*a^1 // : 1/2

2 = a^1

a = 2

a in { -5/2, 2 }

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